(x+y+z)(x-y+z)=(A+B)(A-B)且B=有,则A=

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(x+y+z)(x-y+z)=(A+B)(A-B)且B=有,则A=

(x+y+z)(x-y+z)=(A+B)(A-B)且B=有,则A=
(x+y+z)(x-y+z)=(A+B)(A-B)且B=有,则A=

(x+y+z)(x-y+z)=(A+B)(A-B)且B=有,则A=
B=什么?