y+1=x x+y=1/5(10y+x)y+1=x x+y=1/5(10y+x)2元1次方程
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y+1=x x+y=1/5(10y+x)y+1=x x+y=1/5(10y+x)2元1次方程
y+1=x x+y=1/5(10y+x)
y+1=x
x+y=1/5(10y+x)
2元1次方程
y+1=x x+y=1/5(10y+x)y+1=x x+y=1/5(10y+x)2元1次方程
把y+1=x代入二式
2y+1=1/5(11y+1)
10y+5=11y+1
y=4,
那么x=y+1
=1+4
=5
y=4 x=5
x=y+1 4x=5y
(x+y)/6+(x-y)/10=1,(x+y)/6-(x-y)/10=5
{6/x+y+10/x-y=30 6/x+y-10/x-y=-1
{6(x-y)-7(x+y)=21 {2(x-y)-5(x+y)=-1
(x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5)
y'/y=1/x
{(x+y)/2+(x-y)/3=1,(x+y)-5(x-y)=2.求x=?,y=?
x-y/7 - x+y/10 =1/2 2(x-y)-5(x+y)=3修改、、、、(x-y)/7-(x+y)/10=1/2 2(x-y)-5(x+y)=3
1.5(x+y)+3(x-y)=27(x+y)-3(x-y)=-62.x-y/7 - x+y/10 =1/22(x-y)-5(x+y)=3所谓细节决定成败,
y'-(1/x)y=xe^-x
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
10/x+y+3/x-y=-5 15/x+y-2/x-y=-1(用换元法解此方程组)
{ x-y/7-x+y/10=1/2 {2(x-y)+5(x+y)=3
{ x-y/7-x+y/10=1/2 {2(x-y)+5(x+y)=3
解分式方程:10/(x+y)+3/(x-y)=-5,15/(x+y)-2/(x-y)=-1
3/(X-Y)+10/(X+Y)=-5 2/(X-Y)-15/(X+Y)=1 解分式方程组
分式的加减:[(x/y-y/x)除以(x+y)+x(1/y-1/x)]除以1+x/y,其中x=5,y=2
若5x+y/7x+10y=1/2,则x/y=?
若7x+10y分之5x+y=1/2,则x/y=