四道初一计算题 (1)(8x³-12x²+16x)÷(-4x)(2)[3(m+n)(m-n)+(m-n)²-2nm-n)]÷(4m)(1)(8x³-12x²+16x)÷(-4x)(2)[3(m+n)(m-n)+(m-n)²-2nm-n)]÷(4m)(3)(3x²y-2xy+2xy²)÷(xy)(4

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四道初一计算题 (1)(8x³-12x²+16x)÷(-4x)(2)[3(m+n)(m-n)+(m-n)²-2nm-n)]÷(4m)(1)(8x³-12x²+16x)÷(-4x)(2)[3(m+n)(m-n)+(m-n)²-2nm-n)]÷(4m)(3)(3x²y-2xy+2xy²)÷(xy)(4

四道初一计算题 (1)(8x³-12x²+16x)÷(-4x)(2)[3(m+n)(m-n)+(m-n)²-2nm-n)]÷(4m)(1)(8x³-12x²+16x)÷(-4x)(2)[3(m+n)(m-n)+(m-n)²-2nm-n)]÷(4m)(3)(3x²y-2xy+2xy²)÷(xy)(4
四道初一计算题 (1)(8x³-12x²+16x)÷(-4x)(2)[3(m+n)(m-n)+(m-n)²-2nm-n)]÷(4m)
(1)(8x³-12x²+16x)÷(-4x)
(2)[3(m+n)(m-n)+(m-n)²-2nm-n)]÷(4m)
(3)(3x²y-2xy+2xy²)÷(xy)
(4)[(a+b)(a-b)-(a+b)²]÷(a+b)

四道初一计算题 (1)(8x³-12x²+16x)÷(-4x)(2)[3(m+n)(m-n)+(m-n)²-2nm-n)]÷(4m)(1)(8x³-12x²+16x)÷(-4x)(2)[3(m+n)(m-n)+(m-n)²-2nm-n)]÷(4m)(3)(3x²y-2xy+2xy²)÷(xy)(4
(1)(8x³-12x²+16x)÷(-4x)
=-2x²+3x-4
(2)[3(m+n)(m-n)+(m-n)²-2nm-n)]÷(4m)
=(3m²-3n²+m²-2mn+n²-2nm-n)÷(4m)
=(4m²-2n²-4mn-n)÷(4m)
=4-n²/(2m)-4n-n/(4m) 题目有误?
(3)(3x²y-2xy+2xy²)÷(xy)
=3x-2+2y
(4)[(a+b)(a-b)-(a+b)²]÷(a+b)
=(a-b)-(a+b)
=a-b-a-b
=-2b