作业帮[1/sqrt(2-x)]'为什么等于(1/2)(2-x)^(-3/2)[1/√(2-x)]'=(2-x)^(-1/2)=(-1/2)*(2-x)^(-1/2-1)*(2-x)'=(-1/2)*(2-x)^(-3/2)*(-1)=(1/2)*(2-x)^(-3/2)中的 (2-x)^(-1/2)怎么等于(-1/2)*(2-x)^(-1/2-1)*(2-x)'了？还有[1/√(2-x)]怎么读呀我买见
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/28 16:58:19
![[1/sqrt(2-x)]'为什么等于(1/2)(2-x)^(-3/2)[1/√(2-x)]'=(2-x)^(-1/2)=(-1/2)*(2-x)^(-1/2-1)*(2-x)'=(-1/2)*(2-x)^(-3/2)*(-1)=(1/2)*(2-x)^(-3/2)中的 (2-x)^(-1/2)怎么等于(-1/2)*(2-x)^(-1/2-1)*(2-x)'了？还有[1/√(2-x)]怎么读呀我买见](/uploads/image/z/2583115-43-5.jpg?t=%5B1%2Fsqrt%282-x%29%5D%27%E4%B8%BA%E4%BB%80%E4%B9%88%E7%AD%89%E4%BA%8E%281%2F2%29%282-x%29%5E%28-3%2F2%29%5B1%2F%E2%88%9A%282-x%29%5D%27%3D%282-x%29%5E%28-1%2F2%29%3D%28-1%2F2%29%2A%282-x%29%5E%28-1%2F2-1%29%2A%282-x%29%27%3D%28-1%2F2%29%2A%282-x%29%5E%28-3%2F2%29%2A%28-1%29%3D%281%2F2%29%2A%282-x%29%5E%28-3%2F2%29%E4%B8%AD%E7%9A%84+%282-x%29%5E%28-1%2F2%29%E6%80%8E%E4%B9%88%E7%AD%89%E4%BA%8E%28-1%2F2%29%2A%282-x%29%5E%28-1%2F2-1%29%2A%282-x%29%27%E4%BA%86%EF%BC%9F%E8%BF%98%E6%9C%89%5B1%2F%E2%88%9A%282-x%29%5D%E6%80%8E%E4%B9%88%E8%AF%BB%E5%91%80%E6%88%91%E4%B9%B0%E8%A7%81)
[1/sqrt(2-x)]'为什么等于(1/2)(2-x)^(-3/2)[1/√(2-x)]'=(2-x)^(-1/2)=(-1/2)*(2-x)^(-1/2-1)*(2-x)'=(-1/2)*(2-x)^(-3/2)*(-1)=(1/2)*(2-x)^(-3/2)中的 (2-x)^(-1/2)怎么等于(-1/2)*(2-x)^(-1/2-1)*(2-x)'了？还有[1/√(2-x)]怎么读呀我买见
[1/sqrt(2-x)]'为什么等于(1/2)(2-x)^(-3/2)
[1/√(2-x)]'
=(2-x)^(-1/2)
=(-1/2)*(2-x)^(-1/2-1)*(2-x)'
=(-1/2)*(2-x)^(-3/2)*(-1)
=(1/2)*(2-x)^(-3/2)
中的 (2-x)^(-1/2)怎么等于(-1/2)*(2-x)^(-1/2-1)*(2-x)'了？
还有[1/√(2-x)]怎么读呀我买见过这个符号
[1/sqrt(2-x)]'为什么等于(1/2)(2-x)^(-3/2)[1/√(2-x)]'=(2-x)^(-1/2)=(-1/2)*(2-x)^(-1/2-1)*(2-x)'=(-1/2)*(2-x)^(-3/2)*(-1)=(1/2)*(2-x)^(-3/2)中的 (2-x)^(-1/2)怎么等于(-1/2)*(2-x)^(-1/2-1)*(2-x)'了？还有[1/√(2-x)]怎么读呀我买见
[1/√(2-x)]'
=
=(-1/2)*(2-x)^(-1/2-1)*(2-x)'
=(-1/2)*(2-x)^(-3/2)*(-1)
=(1/2)*(2-x)^(-3/2)
其中的第2步错了
应改为=(-1/2)*(2-x)^(-1/2-1)*(2-x)'
=(-1/2)*(2-x)^(-3/2)*(-1)
[1/√(2-x)]'
=(2-x)^(-1/2)
=(-1/2)*(2-x)^(-1/2-1)*(2-x)'
=(-1/2)*(2-x)^(-3/2)*(-1)
=(1/2)*(2-x)^(-3/2)