若x2+4x+y2-6y+13=0,则(x+2y)(x-2y)的值为----------

来源：学生作业帮助网编辑：作业帮时间：2024/05/17 23:37:22

若x2+4x+y2-6y+13=0,则(x+2y)(x-2y)的值为----------
若x2+4x+y2-6y+13=0,则(x+2y)(x-2y)的值为----------

若x2+4x+y2-6y+13=0,则(x+2y)(x-2y)的值为----------
x2+4x+y2-6y+13=0 (x+2)^2+(y-3)^2=0 x=-2 y=3 (x+2y)(x-2y) =x^2-4y^2 =4-36 =-32