作业帮(1+2xy)^2-(x^2+y^2)^2速求因式分解
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(1+2xy)^2-(x^2+y^2)^2速求因式分解
(1+2xy)^2-(x^2+y^2)^2速求
因式分解
(1+2xy)^2-(x^2+y^2)^2速求因式分解
原式=[(1+2xy)+(x²+y² )][(1+2xy)-(x² +y² )]
=-(x²+y² +2xy+1)(x² +y² -2xy-1)
=-(x²+y² +2xy+1)[(x-y)² -1)]
=-(x²+y² +2xy+1)[(x-y)+1][(x-y)-1]
=-(x-y+1)(x-y-1)(x²+y² +2xy+1)
原式 = [ (1+2xy ) +(x^2 +y^2)] * [(1+2xy) - (x^2+y^2)]
=[ (x+y)^2 +1] * [1- (x-y)^2]
.(x+y-2)(x+y-2xy)+(xy-1)^2
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因式分解x^2y^2+x^2y+xy^2+3xy+x+y+1