(2x-5)^2-(x+4)^2=0,

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(2x-5)^2-(x+4)^2=0,

(2x-5)^2-(x+4)^2=0,
(2x-5)^2-(x+4)^2=0,

(2x-5)^2-(x+4)^2=0,
(2x-5)^2-(x+4)^2=0
[(2x-5)+(x+4)][(2x-5)-(x+4)]=0
[2x-5+x+4][2x-5-x-4]=0
[3x-1][x-9]=0
3x-1=0或x-9=0
所以
x=1/3或9.

(2x-5)^2-(x+4)^2=0
(2x-5-x-4)(2x-5+x+4)=0
(x-9)(3x-1)=0
x=9 or x=1/3

(2x-5)^2-(x+4)^2=0
[(2x-5)+(x+4)][(2x-5)-(x+4)]=0
(3x-1)(x-9)=0
x=1/3或x=9

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