sin(270°+15°)请用两角差的余弦公式求解答案给的是=-cos15°=-cos(60°-45 °)

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/27 20:39:45
sin(270°+15°)请用两角差的余弦公式求解答案给的是=-cos15°=-cos(60°-45 °)

sin(270°+15°)请用两角差的余弦公式求解答案给的是=-cos15°=-cos(60°-45 °)
sin(270°+15°)请用两角差的余弦公式求解
答案给的是=-cos15°=-cos(60°-45 °)

sin(270°+15°)请用两角差的余弦公式求解答案给的是=-cos15°=-cos(60°-45 °)
sin(270°+15°)=sin270°cos15°+cos270°sin15°
=-1*cos15°+0*sin15°
=-cos15°
=-cos(45°-30°)
=-(cos45°cos30°+sin45°sin30°)
=-[(√2/2)*(√3/2)+(√2/2)*(1/2)]
=-(√6+√2)/4

sin(270°+15°)=sin(-85°)=-sin85°=-cos15°=-cos(60°-45 °)
=-(cos60°cos45°+sin60°sin45°)=-0.96593