作业帮求极限lim.[( tanx-sinx) /(sin^2 2x)]
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/27 14:30:01
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求极限lim.[( tanx-sinx) /(sin^2 2x)]
求极限lim.[( tanx-sinx) /(sin^2 2x)]
求极限lim.[( tanx-sinx) /(sin^2 2x)]
lim(x→0) [( tanx-sinx) /(sin^2 2x)]
=lim(x→0) [tanx( 1-cosx) /(2x)^2]=lim(x→0) [x*x^2/2] /(2x)^2=0