(1+1/2-1/3-1/4)*12= 18-6÷ (-2)*|-1/4|= -1^100-(1-0.5)÷3*[3-(-3)^2]=急

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/08 18:32:30
(1+1/2-1/3-1/4)*12= 18-6÷ (-2)*|-1/4|= -1^100-(1-0.5)÷3*[3-(-3)^2]=急

(1+1/2-1/3-1/4)*12= 18-6÷ (-2)*|-1/4|= -1^100-(1-0.5)÷3*[3-(-3)^2]=急
(1+1/2-1/3-1/4)*12= 18-6÷ (-2)*|-1/4|= -1^100-(1-0.5)÷3*[3-(-3)^2]=

(1+1/2-1/3-1/4)*12= 18-6÷ (-2)*|-1/4|= -1^100-(1-0.5)÷3*[3-(-3)^2]=急
(1+1/2-1/3-1/4)*12
=1*12+1/2*12-1/3*12-1/4*12
=12+6-4-3
=11
18-6÷ (-2)*|-1/4|
=18-(-3)*(1/4)
=18+3/4
=75/4
-1^100-(1-0.5)÷3*[3-(-3)^2]
=-1-0.5÷3*(3-9)
=-1+0.5÷3*6
=-1+0.5*2
=-1+1
=0

答案等于 13 吧?

12/(1/2-1/3-1/4)= 2/3-【1/12+1/4】= 4(2x-1)-(10x+1)=3(2x+1)-12 已知1-2/1=2/1,2/1-3/1=6/1,3/1-4/1=12/1,根据这些等式解答下列各题.(1)求值:1/1*2+1/2*3+1/3*4+1/4*5+1/5*6(2)化简:1/1*2+1/2*3+1/3*4+...+1/n(n+1)(3)若1/1*2+1/2*3+1/3*4+...+1/n(n+1)=19/20 (2/1+3/1-4/1)÷12/1=? 观察下列各式 1/6=1/2×3=1/2-1/3 1/12=1/3×4=1/3-1/4 1/20=1/4×5=1/4-1/5(1)猜想:1/n(n+1)=___________ (2)化简:1/(n+1)(n+2)+1/(n+2)(n+3)+1/(n+3)(n+4) 根据例子计算 计算2/1+4/1+8/1可以这样考虑:2/1=1-2/1,4/1=2/1-4/1/,8/4=4/1-8/12/1+4/1+8/1=(1-2/1)+(2/1-4/1)+(4/1-8/1)=1-8/1=8/7求1 2/1+2 4/1+3 8/1+4 16/1+5 32/1+.+10 1024/1 1/3(2x-5)=1/4(x-3)-1/12 有一列数:(1/2)=(1/1-1/2),1/6=(1/2-1/3),1/12=(1/3-1/4),1/20=(1/4-1/5,……)第n个数怎么表示 1/2=1/1*2=1/1-1/2,1/6=1/2*3=1/2-1/3,1/12=1/3*4=1/3-1/4.计算1/(x-2)(x-3)-2/(x-1)(x-3)+1/(x-1)(x-2) (1) 2/12*14+2/14*16+2/16*18+2/18*20+20=(2) 1/(1+2)+ 1/(1+2+3)+ 1/(1+2+3+4)+...+1/(1+2+3+4+...+50)= 在1/2、1/3、1/4、1/5、1/6、1/8、1/12、1/20中,哪几个分数的和=1?1=1/( )+1/( )+1/( ) 1=1/()+1/( )+1/( )+1/( ) 1=1/( )+1/( )+1/( )+1/( )+1/( ) 在计算1/2*1/3=1/6,1/3*1/4=1/12,1/4*1/5=1/20,…时发现:1/6=1/2-1/3,1/12=1/3-1/4,1/20=1/4-1/5,…(1)用含n的式子表示这一变化规律; 观察下列各式:1/1*2=1/1-1/2,1/2*3=1/2-1/3,1/3*4=1/3-1/4.(1)利用上述规律计算1/2+1/6+1/12+...+1/(n-1)n + 1/n(n+1)(2)利用上述规律解方程 1/(x-4)(x-3)+1/(x-3)(x-2)+1/(x-2)(x-1)+1/(x-1)x+1/x(x+1)=1/x+1 12/(4x²-1)+1=2x+3/1-2x 0.25+12/1+(-3/2)-4/1-12/5 找规律填空:1/12,1/6,1/4,1/3,5/12,1/2,(). 6(x-1)+1=3x+17和2(4-x)+1=3(x+1)-12