作业帮计算（2X^2Y-2XY^2)-[(-3X^2Y^2+3X^2Y)+(3X^2Y^2-3XY^2)]X=-1 Y=2
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/05 22:22:23
![计算（2X^2Y-2XY^2)-[(-3X^2Y^2+3X^2Y)+(3X^2Y^2-3XY^2)]X=-1 Y=2](/uploads/image/z/664316-44-6.jpg?t=%E8%AE%A1%E7%AE%97%EF%BC%882X%5E2Y-2XY%5E2%29-%5B%28-3X%5E2Y%5E2%2B3X%5E2Y%29%2B%283X%5E2Y%5E2-3XY%5E2%29%5DX%3D-1+Y%3D2)
计算（2X^2Y-2XY^2)-[(-3X^2Y^2+3X^2Y)+(3X^2Y^2-3XY^2)]X=-1 Y=2
计算（2X^2Y-2XY^2)-[(-3X^2Y^2+3X^2Y)+(3X^2Y^2-3XY^2)]
X=-1 Y=2
计算（2X^2Y-2XY^2)-[(-3X^2Y^2+3X^2Y)+(3X^2Y^2-3XY^2)]X=-1 Y=2
解
（2X^2Y-2XY^2)-[(-3X^2Y^2+3X^2Y)+(3X^2Y^2-3XY^2)]
=(2x^2y-2xy^2)-(3x^2y-3xy^2)
=(2x^2y-3x^2y)+(-2xy^2+3xy^2)
=-x^2y+xy^2
=-xy(x-y)
=-2(-1-2)
=6
