作业帮解下列方程:(1)x^2=36 (2)(2x-1)^2=25 (3)2x^2+7x=0 (4)x^2-6x=-9（5）（x+2)^2=(2x+1)^2(6)9(x+3)^2=(2x-5)^2快哦
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/09 03:43:31
解下列方程:(1)x^2=36 (2)(2x-1)^2=25 (3)2x^2+7x=0 (4)x^2-6x=-9（5）（x+2)^2=(2x+1)^2(6)9(x+3)^2=(2x-5)^2快哦
解下列方程:(1)x^2=36 (2)(2x-1)^2=25 (3)2x^2+7x=0 (4)x^2-6x=-9（5）（x+2)^2=(2x+1)^2
(6)9(x+3)^2=(2x-5)^2
快哦
解下列方程:(1)x^2=36 (2)(2x-1)^2=25 (3)2x^2+7x=0 (4)x^2-6x=-9（5）（x+2)^2=(2x+1)^2(6)9(x+3)^2=(2x-5)^2快哦
(1 ) x^2 - 36=0 (x-6)(x+6) =0 x-6=0 x+6 =0 x1 =6 x2 =-6
(2))(2x-1)^2 - 25 = 0 [( 2x-1)-5 ] [(2x-1)+5 ]=0 ( 2x-1)-5 =0 ( 2x-1)+5 =0
x1=3 x2=-2
(3) x(2x+7)=0 x=0 2x+7=0 x1=0 x2= -7/2
(4) x^2-6x+9=0 (x - 3)^2 =0 x - 3 = 0 x1=x2 = 3
(5) （x+2)^2 -(2x+1)^2 = 0 [(x+2)-(2x+1)]*[(x+2)+(2x+1)]=0 (1-x)(3x+3)=0 1-x=0 3x+3 =0
x1=1 x2=-1
(6)9(x+3)^2 - (2x-5)^2=0 [3(x+3) - (2x - 5)][3(x+3) +(2x - 5)] =0 (x + 14)(5x + 4) = 0
x + 14 =0 5x + 4 =0
x1= -14 x2 = -4/5
（1）x=6or-6
（2）x=3 or x=-2
(3) x=0 or x=负二分之七
（4）x=3
(5)x=1 or x=-1
疯子啊这题谁会啊这是神马题呀