(3+1)(3^2+1)(3^3+1)(3^4+1)(3^5+1)……(3^32+1)

1+2-3-3-3-3=? 1+3+2+1+1x2+3 [(2^3-1)(3^3-1)...100^3-1)]/[(2^3+1)(3^3+1)...(100^3+1)]=? （1+1/2+1/3+... (3+1)(3^2+1)(3^3+1)(3^4+1)…(3^32+1)步骤 1^3+2^3+3^3+...+99^3+100^3 (-1/3)^2除以(-1/3)^3*(1/3)^3除以3^-2*(-3)^0 求和Sn=1+(1+3)+(1+3+3^2)+(1+3+3^2+3^3)+.+(1+3+3^2+3^3+...+3^n-1) 1,1,1,2,2,2,3,3,3,填三阶幻方 3题 1、2、3 求四阶行列式：2 -1 3 2 3 -3 3 2 3 -1 -1 2 3 -1 3 -1 1,1/2,3/2,3/8,( ),( ) 1+1+2+2+3+3+````````````````````````````+99999 1/(2^3)+1/(2^3+1)+1/(2^3+2)+1/(2^3+3)+...+1/(2^4-1) 1+1+1+1+1+1+2+1+8+3+3+3+3+3+3+3+3+3+3+3+3+3+8+3+8+3+8+3+3+8+3+3=? 计算：2(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)+1 计算：(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1) (3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)