作业帮a1=1/2,an=(n²/n²-1)a[n-1]+n/(n+1) (n≥2) 则数列的通项an=
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![a1=1/2,an=(n²/n²-1)a[n-1]+n/(n+1) (n≥2) 则数列的通项an=](/uploads/image/z/7139307-3-7.jpg?t=a1%3D1%2F2%2Can%3D%28n%26%23178%3B%2Fn%26%23178%3B-1%29a%5Bn-1%5D%2Bn%2F%28n%2B1%29+%28n%E2%89%A52%29+%E5%88%99%E6%95%B0%E5%88%97%E7%9A%84%E9%80%9A%E9%A1%B9an%3D)
a1=1/2,an=(n²/n²-1)a[n-1]+n/(n+1) (n≥2) 则数列的通项an=
a1=1/2,an=(n²/n²-1)a[n-1]+n/(n+1) (n≥2) 则数列的通项an=
a1=1/2,an=(n²/n²-1)a[n-1]+n/(n+1) (n≥2) 则数列的通项an=
an=[n²/(n²-1)]a(n-1)+n/(n+1)
[(n+1)/n]an=[n/(n-1)]a(n-1)+1
设bn=[(n+1)/n]an,b1=2a1=1,
bn=b(n-1)+1
bn=b1+n-1=n
[(n+1)/n]an=bn=n
an=n^2/(n+1)