void fun(int *a,int *b) { int *c; c=a;a=b;b=c; } main() { int x=3,y=5,*p=&x,*q=&y; fun(p,q);...void fun(int *a,int *b){int *c;c=a;a=b;b=c;}main(){int x=3,y=5,*p=&x,*q=&y;fun(p,q); printf("%d,%d,",*p,*q);fun(&x,&y); prin"%d,%d\n",*p,*q);}两次调用
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/15 10:55:12
void fun(int *a,int *b) { int *c; c=a;a=b;b=c; } main() { int x=3,y=5,*p=&x,*q=&y; fun(p,q);...void fun(int *a,int *b){int *c;c=a;a=b;b=c;}main(){int x=3,y=5,*p=&x,*q=&y;fun(p,q); printf("%d,%d,",*p,*q);fun(&x,&y); prin"%d,%d\n",*p,*q);}两次调用
void fun(int *a,int *b) { int *c; c=a;a=b;b=c; } main() { int x=3,y=5,*p=&x,*q=&y; fun(p,q);...
void fun(int *a,int *b)
{
int *c;
c=a;a=b;b=c;
}
main()
{
int x=3,y=5,*p=&x,*q=&y;
fun(p,q); printf("%d,%d,",*p,*q);
fun(&x,&y); prin"%d,%d\n",*p,*q);
}
两次调用明明传递的是地址,为什么不能交换x,y的值
void fun(int *a,int *b) { int *c; c=a;a=b;b=c; } main() { int x=3,y=5,*p=&x,*q=&y; fun(p,q);...void fun(int *a,int *b){int *c;c=a;a=b;b=c;}main(){int x=3,y=5,*p=&x,*q=&y;fun(p,q); printf("%d,%d,",*p,*q);fun(&x,&y); prin"%d,%d\n",*p,*q);}两次调用
void fun_1(int **a,int **b)
{
int *c;
c=*a;*a=*b;*b=c;
}
void fun_2(int *a,int *b)
{
int c;
c=*a;*a=*b;*b=c;
}
调用
fun_1(&p,&q); printf("%d,%d\n",*p,*q);
fun_2(&x,&y); printf("%d,%d\n",x,y);