已知sin[(π/4)-x)]=5/13,0<x<π/4.求cos2x/(cosπ/4+已知sin[(π/4)-x)]=5/13,0<x<π/4.求cos2x/[cos(π/4)+x] 已知0<β<π/2<α<π,cos[α-(β/2)]=-1/9,sin[(α/2)-β]=2/3 求cos(α+β) 已知α,β∈(0,π)且tan(α-β)=1/2,ta

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已知sin[(π/4)-x)]=5/13,0<x<π/4.求cos2x/(cosπ/4+已知sin[(π/4)-x)]=5/13,0<x<π/4.求cos2x/[cos(π/4)+x] 已知0<β<π/2<α<π,cos[α-(β/2)]=-1/9,sin[(α/2)-β]=2/3 求cos(α+β) 已知α,β∈(0,π)且tan(α-β)=1/2,ta

已知sin[(π/4)-x)]=5/13,0<x<π/4.求cos2x/(cosπ/4+已知sin[(π/4)-x)]=5/13,0<x<π/4.求cos2x/[cos(π/4)+x] 已知0<β<π/2<α<π,cos[α-(β/2)]=-1/9,sin[(α/2)-β]=2/3 求cos(α+β) 已知α,β∈(0,π)且tan(α-β)=1/2,ta
已知sin[(π/4)-x)]=5/13,0<x<π/4.求cos2x/(cosπ/4+
已知sin[(π/4)-x)]=5/13,0<x<π/4.求cos2x/[cos(π/4)+x] 已知0<β<π/2<α<π,cos[α-(β/2)]=-1/9,sin[(α/2)-β]=2/3 求cos(α+β) 已知α,β∈(0,π)且tan(α-β)=1/2,tanβ=-1/7.求2α-β

已知sin[(π/4)-x)]=5/13,0<x<π/4.求cos2x/(cosπ/4+已知sin[(π/4)-x)]=5/13,0<x<π/4.求cos2x/[cos(π/4)+x] 已知0<β<π/2<α<π,cos[α-(β/2)]=-1/9,sin[(α/2)-β]=2/3 求cos(α+β) 已知α,β∈(0,π)且tan(α-β)=1/2,ta
1.∵sin[(π/4)-x)]=5/13,0<x<π/4 ∴cos[(π/4)-x)]=12/13 cos2x=cos[(π/2)-2x]=2sin[(π/4)-x)]*cos[(π/4)-x)]=2×5/13×12/13=120/169 cos[(π/4)+x]=sin[π/2-(π/4+x)]=sin(π/4-x)=5/13 ∴cos2x/cos[(π/4)+x]=120/169 /5/13 =24/13 2.∵0<β<π/2<α<π 又∵cos[α-(β/2)]=-1/9,sin[(α/2)-β]=2/3 ∴sin[α-(β/2)]=根号80/9,cos[(α/2)-β]=根号5/3 ∴sin[(α+β)/2]=sin{[α-(β/2)]-[(α/2)-β]}=sin[α-(β/2)]cos[(α/2)-β]-sin[(α/2)-β]cos[α-(β/2)]=22/27 cos[(α+β)/2]=根号75/27 cos(α+β)=-根号239/27 3.∵tan(α-β)=1/2 ∴tan(2α-2β)=4/3 ∴tan(2α-β)=tan(2α-β+β)=1 ∵α,β∈(0,π)且tan(α-β)=1/2,tanβ=-1/7 ∴β∈(π/2,π),α∈(0,π/4),∴2α-β∈(-π,0) ∴2α-β=-3π/4 你要给我加分,太难打了!