【1/2xy+y2+1】+【x2-1/2xy-2y2-1】等于多少

2xy-x2+1-y2因式分解 x2-2xy+y2-1分解因式 1-x2-2xy-y2分解因式 分解因式1-x2+2xy-y2 解方程组 x2 -2xy -y2 =1 2x2 -5xy -3y2 =0 解方程组 x2+2xy+y2-4=0 x2-2xy+y2-1=0 分解因式：1、a2b2-0.01 2、-xy-x2-y2 3、x2-xy+四分之一y2 已知x2+4y2+x2y2+1=6xy,则(x4-y4)/(2x2+xy-y2)*(2x-y)/(xy-y2)/(x2+y2/y)2= 【1/2xy+y2+1】+【x2-1/2xy-2y2-1】等于多少 x2—2xy=3y2 2xy+y2=1 怎么解这个方程组? 解方程(x2+y2)2+1=x2+y2+2xy 解方程组：｛x2+y2=13,x2-2xy+y2=1要完整过程！！！~~ 解方程组 ｛3x2-y2=8 {4x2+12xy+9y2=1 {x2+2xy+y2-4=0 x2+xy+y2=4 4x2-9y2=0 x2-2xy+y2-1=0还有{x2+y2=4xy-y2+4=0x2-----x的平方 y2------y的平方 还有{2x-3y=12x2-3xy+y2-4x+3y-3=0 x2-2xy+y2-1/x-y-1 2x2+xy-3y2+x+4y-1因式分解 因式分解：x3+（y-1）x2-2xy-y2 x2-3xy+2y2+y+1怎么因式分解 X2-3xy+2y2+y+1怎么因式分解