Lingo 出错model:max=0.0043*X1+0.0027*X2+0.0025*X3+0.0022*X4+0.0045*X5X2+X3+x4>=4000.6*X1+0.6*X2-0.4*X3-0.4*X4+3.6*X5

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Lingo 出错model:max=0.0043*X1+0.0027*X2+0.0025*X3+0.0022*X4+0.0045*X5X2+X3+x4>=4000.6*X1+0.6*X2-0.4*X3-0.4*X4+3.6*X5

Lingo 出错model:max=0.0043*X1+0.0027*X2+0.0025*X3+0.0022*X4+0.0045*X5X2+X3+x4>=4000.6*X1+0.6*X2-0.4*X3-0.4*X4+3.6*X5
Lingo 出错
model:
max=0.0043*X1+0.0027*X2+0.0025*X3+0.0022*X4+0.0045*X5
X2+X3+x4>=400
0.6*X1+0.6*X2-0.4*X3-0.4*X4+3.6*X5

Lingo 出错model:max=0.0043*X1+0.0027*X2+0.0025*X3+0.0022*X4+0.0045*X5X2+X3+x4>=4000.6*X1+0.6*X2-0.4*X3-0.4*X4+3.6*X5
model:
max=0.0043*X1+0.0027*X2+0.0025*X3+0.0022*X4+0.0045*X5;
X2+X3+x4>=400;
0.6*X1+0.6*X2-0.4*X3-0.4*X4+3.6*X5

Lingo 出错model:max=0.0043*X1+0.0027*X2+0.0025*X3+0.0022*X4+0.0045*X5X2+X3+x4>=4000.6*X1+0.6*X2-0.4*X3-0.4*X4+3.6*X5 lingo程序出错,MODEL:MAX=x1*y4+x2*y1+x3*y2+x4*y3;data:l,d=?;enddatal,d为所放箱子的长宽;x1*l+y1*d lingo简单线性规划问题,老是提醒出错~model:max=0.043*x1+0.027*x2+0.025*x3+0.022*x4+0.045*x5;x1+x2+x3+x4+x5=1000;[ave] 2*x1+2*x2+x3+x4+5*x5 lingo中求最小值问题model:max=x1+x2;-1 lingo程序出错,model:sets:定义行列号;lines/1..31/:line;rows/1..30/:row;网点编号;shop/1..11/:l,r,m,price;人口分布;popu(lines,rows):popudata;distribution(lines,rows,shop):p;endsets目标函数;max=@sum(distribution(I,J,S) | I#ge#1#and#J 求问lingo大神!model:max=3*x11+9*x12-7*x21-x22-x31+5*x32-6*x41;0.5*x11-1.5*x21-0.5*x31-1.5*x41 lingo运行问题Model:max=2.28*y2+4.56*y3+3.34*y4+6.68*y5+12.65*y6;y1*t1+y2*t2+y3*t3+y4*t4+y5*t5+y6*t6 lingo错误,model:max=0.487*(x1+y1)+0.53*(x2+y2)+0.613*(x3+y3)+0.72*(x4+y4)+0.487*(x5+y5)+0.52*(x6+y6)+0.64*(x7+y7);0.487*x1+0.53*x2+0.613*x3+0.72*x4+0.487*x5+0.52*x6+0.64*x7 lingo解非线性方程组的问题.参考书上写的代码:model:x^2+y^2=2;2*x^2+x+y^2+y=4;end解出结果Feasible solution found at iteration:0Variable ValueX 0.4543360Y 1.339247为什么我用lingo这么做总是出错呢? Lingo 那里出错了啊?model:title 物流仓库选址问题lingo求解程序;sets:store/1..12/:w,s,m;sale/1..12/:d;links(store,sale):C,p,x;endsetsdata:从仓库i向销售中心j运送货物的运送总成本;C=100,80,50,50,60,100,120,90,60,100,120, 这个lingo程序错在哪?我编了个lingo程序,测试的时候出错,感激不尽~以下是程序“MODEL:title 码流提取问题;SETS:job/1..5/;worker/1..16/;assign(job,worker):x,a,b;ENDSETSDATA:a=30.8667,32.7657,35.4304,37.781,40.3113,28.6755, lingo程序错误1017model:sets:question(/1..i/):x,y;endsetsinit:x(1)=0;y(1)=0;endinit[obj] max=@sum(link(i,j):c(i))@for(question:(min(@sqrt((x(i)-x(i1))^2+(y(i)-y(j))^2))>=z););@for(question:(max(@sqrt((x(i)-x(i1))^2+(y(i)-y(j))^2)) 帮忙看哈下面这个lingo程序哪里有问题,显示第十行出错,求指导~model:sets:season/1..4/:x;fire/2,3,4/:y;endsetsmin=120+x(1)+x(2)+x(3)+x(4);120*65+x(1)*60>=6000;((120+x(1))*0.85-y(2))*65+60*x(2)>=7500;(((120+x(1))*0.85-y(2)+x(2))*0. lingo中model is illdefined什么意思? 整数规划LINGO求解,max R=20X + 5Y2X + 3Y LINGO求改错目标函数:S= 约束条件:1、xi为5的倍数2、x120,h1133、xi>x(i+1)4、xi+4*hi=dLINGO程序:model:Title 1;sets:jishu/1..14/:x,h;endsets[OBJ] max=((@sum(jishu(i)|i#GT#1:(x(i)*(h(i)-h(i-1)))))+x(1)*h(1))*2;@for(jishu(i):x(i)^ lingo问题,对专业的人来说很简单的.MODEL :SETS:集合段XYI/ @FIL E(′data1txt′) / :x ,y ,r ; 定义变量ENDSETSMIN = R1 - R2 ; 目标函数;下面是约束;R1 = @MAX(XYI(J ) :r (J ) ) ; 找出半径的最大值;R2 = @MIN(XYI(J ) :r (J lingo问题,MODEL :SETS:集合段XYI/ @FIL E(′data1txt′) / :x ,y ,r ; 定义变量ENDSETSMIN = R1 - R2 ; 目标函数;下面是约束;R1 = @MAX(XYI(J ) :r (J ) ) ; 找出半径的最大值;R2 = @MIN(XYI(J ) :r (J ) ) ; 找出半径的最小值;@B