作业帮(1-根号3i)/(根号3+i)^2 求详解!
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(1-根号3i)/(根号3+i)^2 求详解!
(1-根号3i)/(根号3+i)^2
求详解!
(1-根号3i)/(根号3+i)^2 求详解!
原式=(1-√3i)/(√3+i)^2
=(1-√3i)/(2+2√3i)
=(1-√3i)^2/[2*(1-3)]
=(-2-2√3i)/(-4)
=(1+√3i)/2.
原式=(1-√3i)/(√3+i)^2
=(1-√3i)/(2+2√3i)
=(1-√3i)^2/[2*(1-3)]
=(-2-2√3i)/(-4)
=(1+√3i)/2.不对啊~z=(√3+i)/(1-√3i)^2
=(√3+i)/(1-2√3i+3i^2)
=(√3+i)/(-2-2√3i)
=(√3+i)/(-2)(1+√3...
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原式=(1-√3i)/(√3+i)^2
=(1-√3i)/(2+2√3i)
=(1-√3i)^2/[2*(1-3)]
=(-2-2√3i)/(-4)
=(1+√3i)/2.
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