20xy^2+y^2-x+20y^3+xy-y因式分解

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20xy^2+y^2-x+20y^3+xy-y因式分解

20xy^2+y^2-x+20y^3+xy-y因式分解
20xy^2+y^2-x+20y^3+xy-y因式分解

20xy^2+y^2-x+20y^3+xy-y因式分解
1楼不对的.
楼主等一下的额.慢慢说
原式=20y³+20xy²+xy-x-y
= 20y²（x+y)+y(x+y)-(x+y)
=(x+y)(20y²+y-1)
=（x+y)(4y+1)(5y-1)
十字相乘（最后一步

先整理顺序..
得到(20xy^2+20y^3)+(xy+y^2)-(x+y)
因式分解得20y^2(x+y)+y(x+y)-(x+y)
=(x+y)(20y^2+y-1)

原式=y(20y^2+20xy+x+y)-(x+y)
=y（20y+1)(x+y)-(x+y)
=(x+y)(20y^2+y-1)

=20y^2(x+y)+y(y-1)+x(y-1)
=20y^2(x+y)+(y-1)(x+y)
=(x+y)(20y^2+y-1)
=(x+y)(4y+1)(5y-1)

x^2+xy+x=36,y^2+xy+y=20,求x+y. 20xy^2+y^2-x+20y^3+xy-y因式分解 因式分解:12xy^2(y-x)+xy^3(x-y)+4x^2y(x-y) X^Y-2XY^2+y^3 1.6y^2-11y-102.5x^5-15x^3y-20xy^2 已知:x-xy=40,xy-y=-20,求代数式x-y和x+y-2xy的值. x-xy=40,xy-y= -20,求代数式x-y和x+y-2xy算试 已知x-xy=20,xy-y=-10,则x-y=( ),x+y-2xy=( ). 已知x-xy＝20,xy-y＝-10,则x-y＝?x+y-2xy＝? 已知x-xy=20,xy-y=-10,则x-y=?,x+y-2xy? 已知x-xy=20,xy-y=12,则x-y= ,-2xy+x+y= 已知x-xy=20 xy-y=12,则x-y=（ ）,x+y-2xy=（ ）. 已知:x-xy=20,xy-y=12,则x-y=...,-2xy+x+y=... x²-xy-6y²-2x+11y-3;2x²-xy-6y²+3x+8y-2; 3x²+10xy-8y²-11x+26y-20; x²-xy-6y²-2x+11y-3; 2x²-xy-6y²+3x+8y-2; 3x²+10xy-8y²-11x+26y-20; 要过 1、(-7x^y)(2x^y-3xy^3+xy) 2、((x-y)^6)/((y-x)^3)/(x-y) 化简：x-y/x+3y÷x^-y^2/x^2+6xy+9y^2-(xy/x+y) 因式分解 x-xy+3y-3x 2x+xy-y-4x+5y-6