已知平面上3个向量a,b,c 的模均为1.它们相互间夹角为120度.求证(a-b)垂直于c为什么(a-b)*c=ac-bc=|a||c|cos120-|b||c|cos120=0所以a-b)就垂直c

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/28 15:06:28
已知平面上3个向量a,b,c 的模均为1.它们相互间夹角为120度.求证(a-b)垂直于c为什么(a-b)*c=ac-bc=|a||c|cos120-|b||c|cos120=0所以a-b)就垂直c

已知平面上3个向量a,b,c 的模均为1.它们相互间夹角为120度.求证(a-b)垂直于c为什么(a-b)*c=ac-bc=|a||c|cos120-|b||c|cos120=0所以a-b)就垂直c
已知平面上3个向量a,b,c 的模均为1.它们相互间夹角为120度.求证(a-b)垂直于c
为什么(a-b)*c=ac-bc=|a||c|cos120-|b||c|cos120=0
所以a-b)就垂直c

已知平面上3个向量a,b,c 的模均为1.它们相互间夹角为120度.求证(a-b)垂直于c为什么(a-b)*c=ac-bc=|a||c|cos120-|b||c|cos120=0所以a-b)就垂直c
根据定义,两个向量(都不为零向量)相乘为0,则两个向量相互垂直.
(a-b)*c=ac-bc~向量具有分配律
=|a||c|cos120-|b||c|cos120 向量相乘等于两个向量模的乘积再乘以他们之间的夹角
=0

(a-b)*c = |a-b| * |c| *cos A,其中|a-b|是向量a-b的模,不为零(因为a和b有夹角),A是向量a-b与c的夹角。因为(a-b)*c=0,所以A必定为90°或者270°,表明向量a-b垂直于向量c。我的意思是为什么相减等于0就代表垂直你需要这样理a-b是一个新向量(从向量a的终点到向量b的终点的那个向量),它和向量c的乘积为零,表明它们是互相垂直的。 (a-b)...

全部展开

(a-b)*c = |a-b| * |c| *cos A,其中|a-b|是向量a-b的模,不为零(因为a和b有夹角),A是向量a-b与c的夹角。因为(a-b)*c=0,所以A必定为90°或者270°,表明向量a-b垂直于向量c。

收起

Zhuzhou
Red Net News, March 14 (correspondent Tande Hui) CMB owners reversing dumbfound the disputes of others,newport cigarettes sales, had a sorry understanding can be obtained. However, the o...

全部展开

Zhuzhou
Red Net News, March 14 (correspondent Tande Hui) CMB owners reversing dumbfound the disputes of others,newport cigarettes sales, had a sorry understanding can be obtained. However, the owner not only failed to apologize, but gave the driver deliberately drove escape. The face of the masses catch up, he not only did not stop, and driving crashed into two people to catch up. One person injured in the post, and malicious run over their body, causing instant death. March 13, Liling City Procuratorate owners Xiaomou suspicion of manslaughter, submitted to Zhuzhou City Procuratorate for prosecution.
2008 年 12 月 11 morning, blessing God who lives in Town, Liling City, Ridge neighborhood Xiaomou Changsha, Hunan B63022 driving bus for the grades in the blessing of God on the streets of town when reversing, just case of a motorcycle passing by the local villagers Tangmou,cheap monster beats, soup aware of the danger after the emergency brakes,monster beats outlets, car carrying the man fell to the ground. After the fall, Tom see Xiaomou on their own were not ignored, heart anger, Shaw stopped the bus immediately. Fighting this dispute and both sides were open, to persuade the people around, regardless of the car in front Tangmou Xiaomou and others blocked, forcing motorists to Tangmou injured fled the scene.
soup being near the scene of the accident and the motorcycle taxi driver brother Zhou, the text of a car, who immediately rushed to catch up. God Ma ridge road double-plate section, Tom's brother over Xiaomou bus driver, will be placed across the middle of the road motorcycle,cheap newport cigarettes, their own standing on the road on the left indicate Xiaomou parking. See someone out of the way, Shaw not only did not stop, but too hard to hit the steering wheel to the soup brother. Xianshibumiao brother Tom, quickly dodge roadside tree, the Xiaomou see the impact is invalid, a step on the gas to escape forward.
At this point, behind the week, they take the paper arrived with a motorcycle than driving under the Pakistan Xiaomou escape, and in front of about six or seven meters on the right side the road to stop, then get off to a street culture. See the path is blocked, in front of someone knowing Xiaomou case, still ignoring the safety of others, to accelerate the motorcycle collision, resulting in bus front and rear motorcycle collided violently, Zhou remained in the car with people hit with a car on the spot to fly a few meters away the middle of the road. After Xiaomou not only failed to stop, but accelerated and fled the scene. In the escape process, Xiaomou drive again from the Zhou who deliberately run over, resulting in the week died on the spot.
by forensic examination: the deceased Zhou Department of brachiocephalic, left subclavian artery, left common carotid artery rupture caused by hemorrhagic shock and death.
is the source: Red Net Author: Tan Dehui

收起

abc的模都是1
所以abc的绝对值符号相等(模就是绝对值符号,叫距离)

已知平面上3个向量a,b,c的模均为1,它们相互之间的夹角为120度.求证:(a-b)垂直于c. 已知平面上三个向量a、b、c的模均为1,它们之间的夹角均为120度.求证a+b+c=0 已知平面上三个向量a,b,c的模均为1,它们相互之间的夹角为120度.求证:{a-b}垂直c 已知平面上三个向量a,b,c的模都为1,他们相互之间的夹角均为120求证(a—b)垂直c 已知平面上三个向量a,b,c的模均为1,它们相互之间夹角为120度,求证:(a-b)垂直c 已知:a向量、b向量、c向量是同一 个平面内的三个向量,其中向量a=(1,2) 求:(1)若|c|向量=3√5,且c已知:a向量、b向量、c向量是同一 个平面内的三个向量,其中向量a=(1,2) 求:(1)若|c|向量= 已知平面上三个向量a,b,c的模均为1,它们相互之间的夹角为120度.第一:求证(a-b)垂直于c.第二:...已知平面上三个向量a,b,c的模均为1,它们相互之间的夹角为120度.第一:求证(a-b)垂直于 已知平面上三个向量a,b,c,的模为1.已知平面上三个向量a,b,c,的模为1,它们相互之间的夹角均为120度,求证:a⊥(b-c)若|a+kb+c|>1(k∈R),求k的取值范围 已知平面上3个向量a,b,c 的模均为1.它们相互间夹角为120度.求证(a-b)垂直于c为什么(a-b)*c=ac-bc=|a||c|cos120-|b||c|cos120=0所以a-b)就垂直c 已知平面a上的两个向量a=(2,3,1),向量b=(5,6,4),则平面a的一个法向量为多少? 已知平面上3点A B C 满足 向量AB的模=3 向量BC的模=4 向量CA的模=5 求 向量AB·向量BC+向量BC·向量CA+向量CA·向量AB=?很明显,三角形ABC应为以B为直角顶点的直角三角形.所以向量AB和向量BC的夹角的 已知平面向量a,b,c,其中a=(3,4)若c为单位向量且向量a∥向量c 求c的坐标已知平面向量a b c其中a=(3.4)若c为单位向量且向量a∥向量c 求c的坐标若b模=√5 且向量a-2b与 向量2a-b 垂直,求向量a b夹 一道向量计算已知在同一平面内向量a ⊥b ,c 与a的夹角为60度,且a 的模长为1,b的模长为√3,c的模长为2,试求向量F=a+b+c的长度.注:字母均表示向量.c 与b的夹角为60度 a,b,c,为平面内不共线的3个向量,求a*(b+c) 已知平面内三个已知点A(1,7) B(0,0) C(8,3) D为线段BC上的一点 已知平面内三个已知点A(1,7) B(0,0) C(8,3),D为线段BC上的一点,且有(向量BA+向量CA+向量DA)与向量BC垂直,求点D的坐标 已知平面内三个已知点A(1,7) B(0,0) C(8,3) D为线段BC上的一点 已知平面内三个已知点A(1,7) B(0,0) C(8,3),D为线段BC上的一点,且有(向量BA+向量CA+向量DA)与向量BC垂直,求点D的坐标 已知在同一平面内向量a与向量b垂直,向量c与d的夹角为60度,且a的模=1,b的模=根号3,c的模=2求向量r=向量a+向量b+向量c的模不好意思是。向量c与a 的夹角 已知平面上三个向量abc的模均为1,他们相互之间的夹角均为60°求证向量(a-b)垂直于c要过程,或者说明白了也行