作业帮(sin(x)^3+cos(x)^3)的倒数怎么积分
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(sin(x)^3+cos(x)^3)的倒数怎么积分
(sin(x)^3+cos(x)^3)的倒数怎么积分
(sin(x)^3+cos(x)^3)的倒数怎么积分
∫dx/(sinx^3+cosx^3) sinx+cosx=√2cos(x-π/4)
=∫dx/[(sinx+cosx)(1-sinxcosx)] 1-sinxcosx=1-[(sinx+cosx)^2-1]/2=(1/2)-cos(x-π/4)^2
=∫dx/[√2cos(x-π/4)[1/2-cos(x-π/4)^2]
=(1/√2)∫cos(x-π/4)dx/cos(x-π/4)^2[(1/2-cos(x-π/4)^2]
=(1/√2)∫dsin(x-π/4)/[1-sin(x-π/4)^2][sin(x-π/4)^2-1/2]
sin(x-π/4)=u
=(1/√2)∫du/(1-u^2)(u^2-1/2)
=(-1/√2)(2)∫[(1-u^2)+(u^2-1/2)]du/[(1-u^2)(u^2-1/2)]
=(-√2)∫du/(u^2-1/2)+(-√2)∫du/(1-u^2)
= -∫d(√2u)/(2u^2-1) +(-√2/2)ln|(1+u)/(1-u)|
=(1/2)ln|(1+√2u)/(1-√2u)|+(-√2/2)ln|(1+u)/(1-u)|+C
=(1/2)ln|(1+√2sin(x-π/4))/(1-√2sin(x-π/4)|+(-√2/2)ln|(1+sin(x-π/4))/(1-sin(x-π/4))|+C
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