涉及微积分,求图形面积The figure to the right depicts the graphs of y=4-x^2/4 and y=2lnx.The region R lies below the two curves and above the x-axis.Computer the area of R.

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涉及微积分,求图形面积The figure to the right depicts the graphs of y=4-x^2/4 and y=2lnx.The region R lies below the two curves and above the x-axis.Computer the area of R.

涉及微积分,求图形面积The figure to the right depicts the graphs of y=4-x^2/4 and y=2lnx.The region R lies below the two curves and above the x-axis.Computer the area of R.
涉及微积分,求图形面积
The figure to the right depicts the graphs of y=4-x^2/4 and y=2lnx.The region R lies below the two curves and above the x-axis.Computer the area of R.

涉及微积分,求图形面积The figure to the right depicts the graphs of y=4-x^2/4 and y=2lnx.The region R lies below the two curves and above the x-axis.Computer the area of R.
这是一个数值计算的问题.
两个函数的原函数很容易得到,问题在于求两个曲线的交点位置.
f(x)=4-x^2/4 -2lnx 的零点可以用迭代公式:Xn=(16-8ln(Xn-1)),初值如X0=3
更好的方法是用牛顿法,收敛速度更快些:Xn+1=Xn-f(Xn)/f'(Xn)

题目?在哪儿?

耍我啊

=1+1

tine.

英语啊,看不懂啊