lim(x,y)->(0,2)(1-3xy)^2/x

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lim(x,y)->(0,2)(1-3xy)^2/x

lim(x,y)->(0,2)(1-3xy)^2/x
lim(x,y)->(0,2)(1-3xy)^2/x

lim(x,y)->(0,2)(1-3xy)^2/x
请给出完整的题目

lim(x,y)->(0,2)(1-3xy)^2/x lim(x->0)((2-x)/(3-x))^1/x lim(x→+∞,y→0) (1+1/x)^(x^2/(x+y)) lim(x→0y→1)(1+xe^y)^(2y+x/x)求极限 lim(x+y)cos(1/(x^2+y^2))且x,y趋于0 lim(1-x)^(2/x) x->0 1.lim x->∞ (2x/x^2+1)*cosx 2..lim x->∞{ [(x^2-x)arctanx]/x^3-x-5}3..lim x->0 (e^x-e^-x-2x)/(x-sinx) 4..lim x->0 (sinx-x)/(x^3) 5..lim x->0 (x^2*tanx)/(x-tanx) 6..lim x->0 (1+3/x)^2x 7..lim x->0 (1+2x)^(3/sinx) 8.lim x->∞ (x/1+x)^(x-3) 9..li lim(x→0)2x^3-x+1 (lim) x/(x-y) f(x,y)=3xy/x^2+y^2 lim(x→0)(lim(y→0)f(x,y)) 求lim(x→0)x cos 1/x lim(x→∞)x^2/ (3x-1)的极限 lim(x-sinx)/x^3 x趋于0 不用洛必达法则~为什么不能这样做?=lim(1/x^2)-lim(sinx/x*1/x^2)=lim(1/x^2)-lim(1*1/x^2)=0 洛必达法则(1)条件?(2)lim(x->0)P(x)/Q(x)=?已知:lim(x->0)P(x)=A(x),lim(x->0)Q(x)=B(x)可不可以:lim(x->0)P(x)/Q(x)=lim(x->0)A(x)/B(x)(3)lim(x->0)[(1+x)^(1/x)-e]/(cosx-1)=? 1、lim(x->无穷大) e^x arctanx2、lim(x->0)sinx√1+sin(1/x)3、lim(x->无穷大)【(√x^2+x+1)-【(√x^2-x+1)】4、lim(x->无穷大)((x+{x+(x)^0.5]^0.5}^0.5)/(2x+1)^0.55、lim(x->0)(sin3x+x^2sin1/x)/((1+cosx)x)6、lim(n->无穷大)(2^n)(si 求下列极限 1.lim x→0y→2 sin(xy)/x 2.lim x→0y→0 (2-√(xy+4))/xy3.lim x→0y→0(x^2y)/(x^3-y^3) 4.limx→0y→1 xy*sin(1/(x^2+y^2)) 1.lim x->0 sinx/ x 2.lim x趋于0 sin2x/3x 3.lim x趋于0 x乘以cot3x 4.lim x->无穷 sinx/2x 5.limx趋于无穷(1+X/X)2x 6.lim x->0(1+X)1/x 7.lim x->无穷(1-1/X)x 证明下列极限不存在(1) Lim x+y/x-y (2)lim x²y²/ x²y²+(x-y)²(x,y)→(0,0) (x,y)→(0,0) lim x->0 1-cos(3x)/(2x) 和 lim x->0 1-cos3x/2x^2