求证tan(x+y)*tan(x-y)=tan^2x-tan^2y/1-tan^2xtan^2y

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求证tan(x+y)*tan(x-y)=tan^2x-tan^2y/1-tan^2xtan^2y

求证tan(x+y)*tan(x-y)=tan^2x-tan^2y/1-tan^2xtan^2y
求证tan(x+y)*tan(x-y)=tan^2x-tan^2y/1-tan^2xtan^2y

求证tan(x+y)*tan(x-y)=tan^2x-tan^2y/1-tan^2xtan^2y
直接展开,用tan(a+b)=(tana+tanb)/(1-tanatanb)
再用平方差公式